Intercept theorem
AM / AB = AN / AC = MN / BC
Holds when MN is parallel to BC, in the nested figure as well as in the crossed figure.
Calculate a missing length when two intersecting lines are cut by parallel lines, check whether two lines are parallel with the converse, and get a step-by-step solution: ratio equation, cross multiplication and conclusion.
Nested triangles: A, M, B and A, N, C are collinear in that order. Crossed (hourglass) figure: name the smaller triangle AMN; the calculation is the same.
The selected length is calculated as soon as its partner length and one complete ratio (for example AM and AB) are entered.
Enter the partner length of the unknown and one complete ratio of corresponding lengths. Each length of the small triangle AMN must be shorter than the matching length of the large triangle ABC.
Enter AM, AB, AN and AC with AM < AB and AN < AC.
This calculator uses the intercept theorem, also known as Thales’s intercept theorem, the basic proportionality theorem or the side splitter theorem, to find a missing length when two intersecting lines are cut by two parallel lines. Its converse tells you whether two lines are parallel. Every answer comes with a worked solution: the ratio equation written as fractions, the substituted values, the cross multiplication and a concluding sentence.
The intercept theorem states: let lines BM and CN intersect at A. If line MN is parallel to line BC, the corresponding lengths of triangles AMN and ABC are proportional: AM/AB = AN/AC = MN/BC. Triangle AMN is a scaled copy of triangle ABC and all three ratios equal the same scale factor k. A word of caution on names: in English, “Thales’s theorem” usually means a different result, that an angle inscribed in a semicircle is a right angle. The proportionality result used here is best known as the intercept theorem.
Two figures are covered. In the nested figure, M lies on segment AB and N on segment AC, so the small triangle AMN sits inside ABC. In the crossed (hourglass or bowtie) figure, M and B lie on opposite sides of A, as do N and C, and the two triangles meet at their common vertex A. The ratios are written in exactly the same way; in the calculator, simply name the smaller triangle AMN.
To find a length, keep the two ratios that contain the unknown and three known lengths, then cross-multiply. For example, with AM = 3, AB = 5 and AC = 10: 3/5 = AN/10, so AN = 3 × 10 ÷ 5 = 6. The calculator picks a complete ratio automatically, shows this working and rounds to two decimal places when the answer is not exact.
The converse proves that lines are parallel: if A, M, B and A, N, C are collinear in the same order and AM/AB = AN/AC, then MN is parallel to BC. Its contrapositive proves the opposite: if AM/AB ≠ AN/AC, the lines are not parallel. To compare two ratios without rounding, the calculator also checks the cross products AM × AC and AN × AB.
Conditions: the points must be collinear (stated in the problem, not assumed from a sketch), the lines must be given as parallel before you use the theorem, and the points must be in the same order on both lines before you use the converse. A complete written answer names the intersecting lines, the parallel lines and the theorem, writes the ratio equation, shows the calculation and ends with a sentence that includes the unit.
Theorem to find a length, Converse to find out whether MN and BC are parallel.
Select AM, AB, AN, AC, MN or BC; that field becomes the result.
You need the partner of the unknown (AC for AN, for example) and one complete ratio, such as AM and AB.
Ratio equation, substitution, cross multiplication and conclusion are laid out as in a notebook; the button copies them as plain text.
Lines BM and CN intersect at A; points M and N lie on these lines.
AM / AB = AN / AC = MN / BC
Holds when MN is parallel to BC, in the nested figure as well as in the crossed figure.
AN = AM × AC / AB
Same idea for the other lengths: multiply diagonally, then divide by the third value.
k = AM / AB
Triangle AMN is a reduction of triangle ABC by the factor k: MN = k × BC.
AM / AB = AN / AC ⇒ MN ∥ BC
Provided that A, M, B and A, N, C are collinear in the same order.
AM / AB ≠ AN / AC ⇒ MN ∦ BC
Unequal ratios prove that the lines are not parallel.
Check a missing-length problem or a proof of parallel lines and compare your working with a complete solution.
Practise with varied values, exact or rounded answers, and spot ratio mistakes before the test.
Estimate the height of a tree or a building, or the width of a river, with the shadow or sighting method, as Thales did with the pyramid.
Find a dimension on a scale drawing, a scale model or an enlarged figure.
AM/AB = AN/AC gives 3/5 = AN/10, so AN = 3 × 10 ÷ 5 = 6 cm.
Input
AM = 3 cm, AB = 5 cm, AC = 10 cm, MN ∥ BCResult
AN = 6 cmAM/AB = MN/BC gives 4/10 = 6/BC, so BC = 10 × 6 ÷ 4 = 15 cm.
Input
AM = 4 cm, AB = 10 cm, MN = 6 cmResult
BC = 15 cm2.4/6 = 3/AC, so AC = 6 × 3 ÷ 2.4 = 7.5 cm.
Input
AM = 2.4 cm, AB = 6 cm, AN = 3 cmResult
AC = 7.5 cmAN = 3 × 5 ÷ 7 = 15/7, about 2.14 cm to two decimal places.
Input
AM = 3 cm, AB = 7 cm, AC = 5 cmResult
AN ≈ 2.14 cmSun rays are parallel: 2/12 = 1.5/h, so h = 12 × 1.5 ÷ 2 = 9 m.
Input
1.5 m stick, 2 m stick shadow, 12 m tree shadowResult
height = 9 m3/5 = 0.6 and 4.2/7 = 0.6; cross products: 3 × 7 = 21 and 4.2 × 5 = 21.
Input
AM = 3, AB = 5, AN = 4.2, AC = 7Result
MN ∥ BC4 × 11 = 44 but 5 × 9 = 45, so the ratios 4/9 and 5/11 differ.
Input
AM = 4, AB = 9, AN = 5, AC = 11Result
MN not parallel to BCIt states that when two intersecting lines are cut by two parallel lines, the segments they create are proportional: AM/AB = AN/AC = MN/BC. It is also taught as the basic proportionality theorem, the side splitter theorem or the triangle proportionality theorem.
Not in most English-speaking countries, where “Thales’s theorem” means that an angle inscribed in a semicircle is a right angle. In France, Spain, Italy and Portugal, however, the proportionality result on this page is called Thales’ theorem, which is why both names appear.
The theorem starts from parallel lines to calculate a length. The converse starts from AM/AB = AN/AC, with points in the same order, to prove that the lines are parallel. The contrapositive starts from unequal ratios to prove that they are not parallel.
Keep the two ratios that contain the unknown, for example 3/5 = AN/10. Cross-multiplying gives 5 × AN = 3 × 10, so AN = 3 × 10 ÷ 5 = 6: multiply the two diagonal numbers and divide by the third.
Yes. When the two triangles meet at vertex A and point in opposite directions, the ratio equation is the same. Name the smaller triangle AMN and enter its lengths as AM, AN and MN.
The converse only involves the ratios measured along the two intersecting lines, AM/AB and AN/AC. An equality such as AM/AB = MN/BC can hold even when MN and BC are not parallel, so it proves nothing on its own.
When MN is parallel to BC, triangles AMN and ABC are similar: same angles and proportional sides. The common ratio k = AM/AB is the scale factor, so MN = k × BC.
No. The calculations and the worked solution run entirely in your browser, with no account and no data sent anywhere.
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